Is 1-cosh^2(x)=-sinh^2(x) ?

The answer to whether 1-cosh^2(x)=-sinh^2(x) is True

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prove 1-cosh^2(x)=-sinh^2(x)

prove

1 - cosh^{2} (x) = - sinh^{2} (x)

True

Solution steps

1 - cosh^{2} (x) = - sinh^{2} (x)

Use the Hyperbolic identity:

1 = cosh^{2} (x) - sinh^{2} (x)

1 - cosh^{2} (x) = - sinh^{2} (x)

\Rightarrow True

tan^{2} (x) + sec^{2} (x) = 1 - cos (2 x)

cot^{2} (θ) + 1 = csc^{2} (θ)

2 cos (θ) tan (θ) csc (θ) = 2

sec (a) - sec (a) sin^{2} (a) = cos (a)

\frac{( cos ^{2} ( x ) + 4 cos ( x ) + 4 )}{( cos ( x ) + 2 )} = \frac{( 2 sec ( x ) + 1 )}{sec ( x )}

Is 1-cosh^2(x)=-sinh^2(x) ?
The answer to whether 1-cosh^2(x)=-sinh^2(x) is True