Is sin(b)cos^2(b)-sin(b)=-sin^3(b) ?

The answer to whether sin(b)cos^2(b)-sin(b)=-sin^3(b) is True

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prove sin(b)cos^2(b)-sin(b)=-sin^3(b)

prove

sin (b) cos^{2} (b) - sin (b) = - sin^{3} (b)

True

Solution steps

sin (b) cos^{2} (b) - sin (b) = - sin^{3} (b)

Manipulating left side

sin (b) cos^{2} (b) - sin (b)

Rewrite using trig identities

= - sin^{3} (b)

We showed that the two sides could take the same form

\Rightarrow True

\frac{1}{2} (cot (θ) - tan (θ)) = cot (2 θ)

sin^{2} (\frac{x}{2}) = \frac{sec ( x ) - 1}{2 sec ( x )}

cos (θ) + tan (θ) sin (θ) = sec (θ)

cot^{2} (x) + 5 = csc^{2} (x) + 4

\frac{sin ( θ )}{sin ( θ ) - 1} = \frac{1}{1 - csc ( θ )}

Is sin(b)cos^2(b)-sin(b)=-sin^3(b) ?
The answer to whether sin(b)cos^2(b)-sin(b)=-sin^3(b) is True