Is 1+sec(θ)tan(θ)sin(θ)=sec^2(θ) ?

The answer to whether 1+sec(θ)tan(θ)sin(θ)=sec^2(θ) is True

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prove 1+sec(θ)tan(θ)sin(θ)=sec^2(θ)

prove

1 + sec (θ) tan (θ) sin (θ) = sec^{2} (θ)

True

Solution steps

1 + sec (θ) tan (θ) sin (θ) = sec^{2} (θ)

Manipulating left side

1 + sec (θ) tan (θ) sin (θ)

Rewrite using trig identities

= sec^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

2 - cos^{2} (θ) = 1 + sin^{2} (θ)

(tan (x)) (sin (x)) + cos (x) = sec (x)

sin (x) + sin (x) \cdot cot^{2} (x) = csc (x)

\frac{1 - cos ^{2} ( θ )}{sin ( θ )} = sin (θ)

1 + sec^{2} (x) \cdot sin^{2} (x) = sec^{2} (x)

Is 1+sec(θ)tan(θ)sin(θ)=sec^2(θ) ?
The answer to whether 1+sec(θ)tan(θ)sin(θ)=sec^2(θ) is True