Is sec^2(x)+tan^2(x)sec^2(x)=sec^4(x) ?

The answer to whether sec^2(x)+tan^2(x)sec^2(x)=sec^4(x) is True

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prove sec^2(x)+tan^2(x)sec^2(x)=sec^4(x)

prove

sec^{2} (x) + tan^{2} (x) sec^{2} (x) = sec^{4} (x)

True

Solution steps

sec^{2} (x) + tan^{2} (x) sec^{2} (x) = sec^{4} (x)

Manipulating left side

sec^{2} (x) + tan^{2} (x) sec^{2} (x)

Rewrite using trig identities

= sec^{4} (x)

We showed that the two sides could take the same form

\Rightarrow True

cos (7 5^{\circ}) = cos (4 5^{\circ} + 3 0^{\circ})

\frac{1}{1 + cot ^{2} ( x )} = sin^{2} (x)

sec (θ) \cdot sin (θ) = tan (θ)

1 - sin (x) = (sin (\frac{x}{2}) - cos (\frac{x}{2}))^{2}

sin (θ) = cos (\frac{π}{2} - θ)

Is sec^2(x)+tan^2(x)sec^2(x)=sec^4(x) ?
The answer to whether sec^2(x)+tan^2(x)sec^2(x)=sec^4(x) is True