Is 2cos(a+b)sin(b)=sin(a+2b)-sin(a) ?

The answer to whether 2cos(a+b)sin(b)=sin(a+2b)-sin(a) is True

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prove 2cos(a+b)sin(b)=sin(a+2b)-sin(a)

prove

2 cos (a + b) sin (b) = sin (a + 2 b) - sin (a)

True

Solution steps

2 cos (a + b) sin (b) = sin (a + 2 b) - sin (a)

Manipulating left side

2 cos (a + b) sin (b)

Rewrite using trig identities

= sin (a + 2 b) - sin (a)

We showed that the two sides could take the same form

\Rightarrow True

\frac{1}{1 + sin ^{2} ( a )} + \frac{1}{1 + csc ^{2} ( a )} = 1

sin^{2} (t) + cos^{2} (t) = 1

tan (- x) = tan (x)

cos^{2} (x) = (1 + sin (x)) (1 - sin (x))

tan (x) - sec (x) = \frac{sin ( x ) - 1}{cos ( x )}

Is 2cos(a+b)sin(b)=sin(a+2b)-sin(a) ?
The answer to whether 2cos(a+b)sin(b)=sin(a+2b)-sin(a) is True