Is tan(2x)-sin(2x)=tan(2x)sin(2x) ?

The answer to whether tan(2x)-sin(2x)=tan(2x)sin(2x) is False

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prove tan(2x)-sin(2x)=tan(2x)sin(2x)

prove

tan (2 x) - sin (2 x) = tan (2 x) sin (2 x)

False

Solution steps

tan (2 x) - sin (2 x) = tan (2 x) sin (2 x)

Show that the two sides are not equal

For

tan (2 x) - sin (2 x) = tan (2 x) sin (2 x)

plug in

x = 1

tan (2 \cdot 1) - sin (2 \cdot 1) = - 3.09433 \dots

tan (2 \cdot 1) - sin (2 \cdot 1)

Refine to a decimal form

= - 3.09433 \dots

tan (2 \cdot 1) sin (2 \cdot 1) = - 1.98685 \dots

tan (2 \cdot 1) sin (2 \cdot 1)

Refine to a decimal form

= - 1.98685 \dots

The two sides are not equal

\Rightarrow False

tan^{2} (x) + sec^{2} (x) = 1

sec (x) tan (x) - sin (x) = sin (x) tan^{2} (x)

\frac{1 - cos ( 2 x )}{csc ( x )} = 2 sin^{3} (x)

(1 + sin (x))^{2} + cos^{2} (x) = 2 (1 + sin (x))

\frac{2 - sec ^{2} ( x )}{sec ^{2} ( x )} = cos (2 x)

Is tan(2x)-sin(2x)=tan(2x)sin(2x) ?
The answer to whether tan(2x)-sin(2x)=tan(2x)sin(2x) is False