Is sin^2(θ)sec^2(θ)csc^2(θ)=sec^2(θ) ?

The answer to whether sin^2(θ)sec^2(θ)csc^2(θ)=sec^2(θ) is True

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prove sin^2(θ)sec^2(θ)csc^2(θ)=sec^2(θ)

prove

sin^{2} (θ) sec^{2} (θ) csc^{2} (θ) = sec^{2} (θ)

True

Solution steps

sin^{2} (θ) sec^{2} (θ) csc^{2} (θ) = sec^{2} (θ)

Manipulating left side

sin^{2} (θ) sec^{2} (θ) csc^{2} (θ)

Express with sin, cos

= \frac{1}{cos ^{2} ( θ )}

Rewrite using trig identities

sec^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

\frac{csc ( θ ) - sin ( θ )}{sin ( θ )} = cot^{2} (θ)

\frac{csc ^{2} ( x )}{cot ( x )} = sec (x) csc (x)

csc (x) sin (x) = 1

(sin (x) + cos (x))^{2} = 1 - sin (2 x)

\frac{cos ( A )}{1 + sin ( A )} + \frac{cos ( A )}{1 - sin ( A )} = 2 sec (A)

Is sin^2(θ)sec^2(θ)csc^2(θ)=sec^2(θ) ?
The answer to whether sin^2(θ)sec^2(θ)csc^2(θ)=sec^2(θ) is True