Is sin^2(x+xy)+cos^2(x+xy)=1 ?

The answer to whether sin^2(x+xy)+cos^2(x+xy)=1 is True

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prove sin^2(x+xy)+cos^2(x+xy)=1

prove

sin^{2} (x + x y) + cos^{2} (x + x y) = 1

True

Solution steps

sin^{2} (x + x y) + cos^{2} (x + x y) = 1

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

\Rightarrow True

\frac{1}{csc ^{2} ( θ )} = cos^{2} (θ) + 1

sin (\frac{17 π}{2} + x) = cos (x)

\frac{cos ^{2} ( θ )}{1 + sin ( θ )} = 1 - sin (θ)

4 sin (3 θ) = 12 sin (θ) - 16 sin^{3} (θ)

tan^{2} (x) + \frac{1}{sin ( x ) csc ( x )} = sec^{2} (x)

Is sin^2(x+xy)+cos^2(x+xy)=1 ?
The answer to whether sin^2(x+xy)+cos^2(x+xy)=1 is True