Is (8sin^2(t))/(tan^2(t))=8cos^2(t) ?

The answer to whether (8sin^2(t))/(tan^2(t))=8cos^2(t) is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove (8sin^2(t))/(tan^2(t))=8cos^2(t)

prove

\frac{8 sin ^{2} ( t )}{tan ^{2} ( t )} = 8 cos^{2} (t)

True

Solution steps

\frac{8 sin ^{2} ( t )}{tan ^{2} ( t )} = 8 cos^{2} (t)

Manipulating left side

\frac{8 sin ^{2} ( t )}{tan ^{2} ( t )}

Express with sin, cos

= 8 cos^{2} (t)

We showed that the two sides could take the same form

\Rightarrow True

\frac{sin ( θ ) + sin ( 3 θ )}{2 cos ( θ )} = sin (2 θ)

tan^{2} (θ) = \frac{1}{cos ^{2} ( θ )} - 1

sin (x) cos (x) tan (x) = 1 - cos^{2} (x)

\frac{1 + tan ( u )}{1 + cot ( u )} = tan (u)

sec^{2} (B) = \frac{1}{1 - sin ^{2} ( B )}

Is (8sin^2(t))/(tan^2(t))=8cos^2(t) ?
The answer to whether (8sin^2(t))/(tan^2(t))=8cos^2(t) is True