Is (sin^2(x))/(cos(x)-1)=-1-cos(x) ?

The answer to whether (sin^2(x))/(cos(x)-1)=-1-cos(x) is True

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prove (sin^2(x))/(cos(x)-1)=-1-cos(x)

prove

\frac{sin ^{2} ( x )}{cos ( x ) - 1} = - 1 - cos (x)

True

Solution steps

\frac{sin ^{2} ( x )}{cos ( x ) - 1} = - 1 - cos (x)

Manipulating left side

\frac{sin ^{2} ( x )}{cos ( x ) - 1}

Rewrite using trig identities

= - cos (x) - 1

= - 1 - cos (x)

We showed that the two sides could take the same form

\Rightarrow True

sin (θ + \frac{π}{3}) = sin (θ) + sin (\frac{π}{3})

arcsec (x) = cos (x)

(csc (θ) - cot (θ)) (1 + sec (θ)) = tan (θ)

\frac{1 - sin ^{2} ( b )}{cos ( b )} = cos (b)

\frac{1 + csc ( θ )}{cot ( θ ) + cos ( θ )} = sec (θ)

Is (sin^2(x))/(cos(x)-1)=-1-cos(x) ?
The answer to whether (sin^2(x))/(cos(x)-1)=-1-cos(x) is True