Is 2sin^2(x)-sin(x)-1=0 ?

The answer to whether 2sin^2(x)-sin(x)-1=0 is False

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prove 2sin^2(x)-sin(x)-1=0

prove

2 sin^{2} (x) - sin (x) - 1 = 0

False

Solution steps

2 sin^{2} (x) - sin (x) - 1 = 0

Show that the two sides are not equal

\Rightarrow False

2 cos^{2} (θ) - 1 = cos (2 θ)

cos (3 B) = cos (B) (cos^{2} (B) - 3 sin^{2} (B))

tan (2 x) = \frac{1}{1 - tan ( x )} - \frac{1}{1 + tan ( x )}

sin (θ + \frac{π}{2}) = cos (θ)

sin (2 x) = \frac{2 cot ( x )}{csc ^{2} ( x )}