Is (cot^2(x))/(cos^2(x))=csc^2(x) ?

The answer to whether (cot^2(x))/(cos^2(x))=csc^2(x) is True

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prove (cot^2(x))/(cos^2(x))=csc^2(x)

prove

\frac{cot ^{2} ( x )}{cos ^{2} ( x )} = csc^{2} (x)

True

Solution steps

\frac{cot ^{2} ( x )}{cos ^{2} ( x )} = csc^{2} (x)

Manipulating left side

\frac{cot ^{2} ( x )}{cos ^{2} ( x )}

Express with sin, cos

= \frac{1}{sin ^{2} ( x )}

Rewrite using trig identities

csc^{2} (x)

We showed that the two sides could take the same form

\Rightarrow True

cos (x) - 1 = \frac{cos ( 2 x ) - 1}{2 ( cos ( x ) + 1 )}

sec (x) = arccos (x)

tan (θ) + sin (θ) = 4 (1 + cos (θ))

\frac{2}{cot ( x ) tan ( x )} = sin (2 x)

(sin (x) - cos (x))^{2} = 1 + sin (2 x)

Is (cot^2(x))/(cos^2(x))=csc^2(x) ?
The answer to whether (cot^2(x))/(cos^2(x))=csc^2(x) is True