Is 4sin^2(x)+2cos^2(x)=4-2cos^2(x) ?

The answer to whether 4sin^2(x)+2cos^2(x)=4-2cos^2(x) is True

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prove 4sin^2(x)+2cos^2(x)=4-2cos^2(x)

prove

4 sin^{2} (x) + 2 cos^{2} (x) = 4 - 2 cos^{2} (x)

True

Solution steps

4 sin^{2} (x) + 2 cos^{2} (x) = 4 - 2 cos^{2} (x)

Manipulating left side

4 sin^{2} (x) + 2 cos^{2} (x)

Rewrite using trig identities

= 4 - 2 cos^{2} (x)

We showed that the two sides could take the same form

\Rightarrow True

sin (\frac{x}{2}) \cdot cos (\frac{x}{2}) = \frac{1}{2} sin (x)

2 cos (4 θ) + 5 = 16 sin^{2} (θ)

cos^{2} (r) - 1 = - sin^{2} (r)

\frac{tan ^{2} ( θ )}{sin ( θ )} = sec (θ) tan (θ)

\frac{csc ^{2} ( x )}{csc ^{2} ( x ) - 1} = sec^{2} (x)

Is 4sin^2(x)+2cos^2(x)=4-2cos^2(x) ?
The answer to whether 4sin^2(x)+2cos^2(x)=4-2cos^2(x) is True