Is (csc^2(x))/(cot(x))=csc(x)*sec(x) ?

The answer to whether (csc^2(x))/(cot(x))=csc(x)*sec(x) is True

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prove (csc^2(x))/(cot(x))=csc(x)*sec(x)

prove

\frac{csc ^{2} ( x )}{cot ( x )} = csc (x) \cdot sec (x)

True

Solution steps

\frac{csc ^{2} ( x )}{cot ( x )} = csc (x) sec (x)

Manipulating left side

\frac{csc ^{2} ( x )}{cot ( x )}

Express with sin, cos

= \frac{1}{cos ( x ) sin ( x )}

Rewrite using trig identities

sec (x) csc (x)

= csc (x) sec (x)

We showed that the two sides could take the same form

\Rightarrow True

(1 - sin (x)) + (1 + sin (x)) = 2 cos (x)

- \frac{1}{sin ( x )} = - csc (x)

tan^{2} (θ) + 4 = sec^{2} (θ) + 3

\frac{sin ^{2} ( a )}{1 + cos ( a )} = 1 - cos (a)

\frac{1}{1 - sin ( β )} + \frac{1}{1 + sin ( β )} = 2 sec^{2} (β)

Is (csc^2(x))/(cot(x))=csc(x)*sec(x) ?
The answer to whether (csc^2(x))/(cot(x))=csc(x)*sec(x) is True