Is 1+tan^2(x)=cos^2(x)+sin^2(x) ?

The answer to whether 1+tan^2(x)=cos^2(x)+sin^2(x) is False

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prove 1+tan^2(x)=cos^2(x)+sin^2(x)

prove

1 + tan^{2} (x) = cos^{2} (x) + sin^{2} (x)

False

Solution steps

1 + tan^{2} (x) = cos^{2} (x) + sin^{2} (x)

Show that the two sides are not equal

\Rightarrow False

cot^{2} (A) - cos^{2} (A) = cot^{2} (A) cos^{2} (A)

cos^{2} (2 t) + sin^{2} (2 t) = 1

tan (α) + cot (2 α) = sec (2 α)

tan (x + \frac{π}{3}) = \frac{tan ( x ) + 3}{1 - 3 tan ( x )}

csc (x^{4}) - cot (x^{4}) = 2 csc (x) - 1

Is 1+tan^2(x)=cos^2(x)+sin^2(x) ?
The answer to whether 1+tan^2(x)=cos^2(x)+sin^2(x) is False