Is sin(3θ)+sin(θ)=2sin(θ)cos(θ) ?

The answer to whether sin(3θ)+sin(θ)=2sin(θ)cos(θ) is False

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prove sin(3θ)+sin(θ)=2sin(θ)cos(θ)

prove

sin (3 θ) + sin (θ) = 2 sin (θ) cos (θ)

False

Solution steps

sin (3 θ) + sin (θ) = 2 sin (θ) cos (θ)

Show that the two sides are not equal

\Rightarrow False

(1 - cos^{2} (a)) (1 + tan^{2} (a)) = tan^{2} (a)

\frac{1}{sin ( \frac{13}{5} )} = csc (\frac{13}{5})

tan (\frac{θ}{2}) = \frac{1 - cos ( θ )}{2}

- csc (x) + sin (x) = - cos (x) cot (x)

\frac{cos ( x ) + sin ( x )}{sin ( x )} - cot (x) = 1

Is sin(3θ)+sin(θ)=2sin(θ)cos(θ) ?
The answer to whether sin(3θ)+sin(θ)=2sin(θ)cos(θ) is False