Is 1-(sin(x)+cos(x))^2=-sin(2x) ?

The answer to whether 1-(sin(x)+cos(x))^2=-sin(2x) is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove 1-(sin(x)+cos(x))^2=-sin(2x)

prove

1 - (sin (x) + cos (x))^{2} = - sin (2 x)

True

Solution steps

1 - (sin (x) + cos (x))^{2} = - sin (2 x)

Manipulating left side

1 - (sin (x) + cos (x))^{2}

Rewrite using trig identities

= - sin (2 x)

We showed that the two sides could take the same form

\Rightarrow True

\frac{tan ^{2} ( x ) + 1}{tan ^{2} ( x )} = csc^{2} (x)

sin (7 x) + sin (x) = 2 cos (3 x) sin (4 x)

\frac{csc ( 4 x ) - cot ( 4 x )}{csc ( 4 x ) + cot ( 4 x )} = tan (2 x)

(cos (\frac{x}{2}) - sin (\frac{x}{2}))^{2} = 1 - sin (x)

2 cos^{2} (w) - 1 = 1 - 2 sin^{2} (w)

Is 1-(sin(x)+cos(x))^2=-sin(2x) ?
The answer to whether 1-(sin(x)+cos(x))^2=-sin(2x) is True