Is sin^2(t/2)=(1-cos(t))/2 ?

The answer to whether sin^2(t/2)=(1-cos(t))/2 is True

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prove sin^2(t/2)=(1-cos(t))/2

prove

sin^{2} (\frac{t}{2}) = \frac{1 - cos ( t )}{2}

True

Solution steps

sin^{2} (\frac{t}{2}) = \frac{1 - cos ( t )}{2}

Let:

u = \frac{t}{2}

sin^{2} (u) = \frac{1 - cos ( 2 u )}{2}

Prove

sin^{2} (u) = \frac{1 - cos ( 2 u )}{2} :

True

Therefore

sin^{2} (\frac{t}{2}) = \frac{1 - cos ( t )}{2}

We showed that the two sides could take the same form

\Rightarrow True

cos (θ) = (sec (θ) + tan (θ)) (1 - sin (θ))

\frac{cos ( x )}{sin ( 2 x )} = \frac{1}{2 sin ( x )}

sec (2 x) = \frac{1}{cos ( 2 x )}

(sin (x) + cos (x)) 2 = 1 + sin (2 x)

cot (x) cos (x) = csc (x) - sin (x)

Is sin^2(t/2)=(1-cos(t))/2 ?
The answer to whether sin^2(t/2)=(1-cos(t))/2 is True