Is sec(2α)2-sec(2α)=sec(2α) ?

The answer to whether sec(2α)2-sec(2α)=sec(2α) is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove sec(2α)2-sec(2α)=sec(2α)

prove

sec (2 α) 2 - sec (2 α) = sec (2 α)

True

Solution steps

sec (2 α) \cdot 2 - sec (2 α) = sec (2 α)

Manipulating left side

sec (2 α) 2 - sec (2 α)

Simplify

= sec (2 α)

We showed that the two sides could take the same form

\Rightarrow True

\frac{sin ( 2 θ )}{sin ( 4 θ )} = \frac{1}{2} sec (2 θ)

\frac{sin ( 2 x )}{cos ( x )} = 2 sin (x)

1 - cos^{2} (2 x) = sin^{2} (2 x)

\frac{cos ^{2} ( x ) - 1}{cos ( x ) - 1} = cos (x) + 1

cosh^{(2)} (x) - sinh^{(2)} (x) = 1

Is sec(2α)2-sec(2α)=sec(2α) ?
The answer to whether sec(2α)2-sec(2α)=sec(2α) is True