Is 1+sec(θ)sin(θ)tan(θ)=sec^2(θ) ?

The answer to whether 1+sec(θ)sin(θ)tan(θ)=sec^2(θ) is True

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prove 1+sec(θ)sin(θ)tan(θ)=sec^2(θ)

prove

1 + sec (θ) sin (θ) tan (θ) = sec^{2} (θ)

True

Solution steps

1 + sec (θ) sin (θ) tan (θ) = sec^{2} (θ)

Manipulating left side

1 + sec (θ) sin (θ) tan (θ)

Rewrite using trig identities

= sec^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

\frac{sin ( 2 α )}{1 + cos ( 2 α )} = tan (α)

cos (t) + tan (t) sin (t) = sec (t)

\frac{1 - cos ( x )}{- 1 + \frac{1}{c o s ( x )}} = cos (x)

cos^{4} (x) - sin^{4} (x) = tan^{2} (x)

(cos (x) - sin (x))^{2} = 1 - 2 sin (x) \cdot cos (x)

Is 1+sec(θ)sin(θ)tan(θ)=sec^2(θ) ?
The answer to whether 1+sec(θ)sin(θ)tan(θ)=sec^2(θ) is True