Is sin(θ)= 4/3 sin^3(θ)+1/3 sin^3(θ) ?

The answer to whether sin(θ)= 4/3 sin^3(θ)+1/3 sin^3(θ) is False

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prove sin(θ)= 4/3 sin^3(θ)+1/3 sin^3(θ)

prove

sin (θ) = \frac{4}{3} sin^{3} (θ) + \frac{1}{3} sin^{3} (θ)

False

Solution steps

sin (θ) = \frac{4}{3} sin^{3} (θ) + \frac{1}{3} sin^{3} (θ)

Show that the two sides are not equal

\Rightarrow False

sin (x - \frac{3 π}{2}) + sin (\frac{π}{2} + x) = 2 cos (x)

\frac{1}{cos ( x ) \cdot sin ( x )} - tan (x) = cot (x)

\frac{1}{csc ( x ) - 1} = sin (x) - 1

sec^{2} (x) cot^{2} (x) = csc^{2} (x)

sin (θ) + cot (θ) cos (θ) = csc (θ)

Is sin(θ)= 4/3 sin^3(θ)+1/3 sin^3(θ) ?
The answer to whether sin(θ)= 4/3 sin^3(θ)+1/3 sin^3(θ) is False