Is ((tan^2(x)+1))/(sec(x))=sec(x) ?

The answer to whether ((tan^2(x)+1))/(sec(x))=sec(x) is True

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prove ((tan^2(x)+1))/(sec(x))=sec(x)

prove

\frac{( tan ^{2} ( x ) + 1 )}{sec ( x )} = sec (x)

True

Solution steps

\frac{tan ^{2} ( x ) + 1}{sec ( x )} = sec (x)

Manipulating left side

\frac{tan ^{2} ( x ) + 1}{sec ( x )}

Rewrite using trig identities

= sec (x)

We showed that the two sides could take the same form

\Rightarrow True

csc^{2} (x) cos (2 x) = 1 - tan^{2} (x)

\frac{2 tan ( θ )}{1 - tan ^{2} ( θ )} = tan (2 θ)

cos (x) sin (x) = \frac{1}{2} sin (2 x)

\frac{1 + tan ( x )}{1 - tan ( x )} = tan (x + \frac{π}{4})

4 sin (x) cos (x) = 2 sin (2 x)

Is ((tan^2(x)+1))/(sec(x))=sec(x) ?
The answer to whether ((tan^2(x)+1))/(sec(x))=sec(x) is True