Is csc(x)-sec(x)sin^2(x)=cos(x) ?

The answer to whether csc(x)-sec(x)sin^2(x)=cos(x) is False

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prove csc(x)-sec(x)sin^2(x)=cos(x)

prove

csc (x) - sec (x) sin^{2} (x) = cos (x)

False

Solution steps

csc (x) - sec (x) sin^{2} (x) = cos (x)

Show that the two sides are not equal

For

csc (x) - sec (x) sin^{2} (x) = cos (x)

plug in

x = 1

csc (1) - sec (1) sin^{2} (1) = - 0.12211 \dots

csc (1) - sec (1) sin^{2} (1)

Refine to a decimal form

= - 0.12211 \dots

cos (1) = 0.54030 \dots

cos (1)

Refine to a decimal form

= 0.54030 \dots

The two sides are not equal

\Rightarrow False

tan^{2} (x) + 4 = sec^{2} (x) + 3

\frac{( 1 - csc ( x ) )}{cos ( x ) - cot ( x )} = sec (x)

sin (x - \frac{π}{2}) = cos (x)

cos^{2} (x) - cos^{2} (x) = 0

sec (x) sin (x) cot (x) = 1

Is csc(x)-sec(x)sin^2(x)=cos(x) ?
The answer to whether csc(x)-sec(x)sin^2(x)=cos(x) is False