Is (csc(x)-cot(x))(sec(x)1)=tan(x) ?

The answer to whether (csc(x)-cot(x))(sec(x)1)=tan(x) is False

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prove (csc(x)-cot(x))(sec(x)1)=tan(x)

prove

(csc (x) - cot (x)) (sec (x) 1) = tan (x)

False

Solution steps

(csc (x) - cot (x)) sec (x) \cdot 1 = tan (x)

Show that the two sides are not equal

For

(csc (x) - cot (x)) sec (x) 1 = tan (x)

plug in

x = 1

(csc (1) - cot (1)) sec (1) \cdot 1 = 1.01110 \dots

(csc (1) - cot (1)) sec (1) \cdot 1

Refine to a decimal form

= 1.01110 \dots

tan (1) = 1.55740 \dots

tan (1)

Refine to a decimal form

= 1.55740 \dots

The two sides are not equal

\Rightarrow False

- \frac{cos ^{2} ( x )}{sin ( x )} = - cos (x) cot (x)

tan^{3} (x) - tan (x) sec^{2} (x) = tan (- x)

sec (π - x) = - sec (x)

sin (- x) - cos (- x) = - (sin (x) + cos (x))

sec (a) - cos (a) csc (a) - sin (a) = tan (3 a)

Is (csc(x)-cot(x))(sec(x)1)=tan(x) ?
The answer to whether (csc(x)-cot(x))(sec(x)1)=tan(x) is False