Is sin^2(t)=(1-cos(2t))/2 ?

The answer to whether sin^2(t)=(1-cos(2t))/2 is True

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prove sin^2(t)=(1-cos(2t))/2

prove

sin^{2} (t) = \frac{1 - cos ( 2 t )}{2}

True

Solution steps

sin^{2} (t) = \frac{1 - cos ( 2 t )}{2}

Manipulating right side

\frac{1 - cos ( 2 t )}{2}

Rewrite using trig identities

\frac{1 - cos ( 2 t )}{2}

Use the Double Angle identity:

cos (2 x) = 1 - 2 sin^{2} (x)

= \frac{1 - ( 1 - 2 sin ^{2} ( t ) )}{2}

Simplify

\frac{1 - ( 1 - 2 sin ^{2} ( t ) )}{2} : sin^{2} (t)

\frac{1 - ( 1 - 2 sin ^{2} ( t ) )}{2}

Expand

1 - (1 - 2 sin^{2} (t)) : 2 sin^{2} (t)

1 - (1 - 2 sin^{2} (t))

- (1 - 2 sin^{2} (t)) : - 1 + 2 sin^{2} (t)

- (1 - 2 sin^{2} (t))

Distribute parentheses

= - (1) - (- 2 sin^{2} (t))

Apply minus-plus rules

- (- a) = a, - (a) = - a

= - 1 + 2 sin^{2} (t)

= 1 - 1 + 2 sin^{2} (t)

1 - 1 = 0

= 2 sin^{2} (t)

= \frac{2 sin ^{2} ( t )}{2}

Divide the numbers:

\frac{2}{2} = 1

= sin^{2} (t)

= sin^{2} (t)

= sin^{2} (t)

We showed that the two sides could take the same form

\Rightarrow True

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Is sin^2(t)=(1-cos(2t))/2 ?
The answer to whether sin^2(t)=(1-cos(2t))/2 is True