Is sin(z+w)=sin(z)cos(w)+cos(z)sin(w) ?

The answer to whether sin(z+w)=sin(z)cos(w)+cos(z)sin(w) is True

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prove sin(z+w)=sin(z)cos(w)+cos(z)sin(w)

prove

sin (z + w) = sin (z) cos (w) + cos (z) sin (w)

True

Solution steps

sin (z + w) = sin (z) cos (w) + cos (z) sin (w)

Use the Angle Sum identity:

sin (s + t) = sin (s) cos (t) + cos (s) sin (t)

\Rightarrow True

tan^{2} (x) = \frac{( 1 - cos ( 2 x ) )}{1 + cos ( 2 x )}

sin (2 x) = 2 sin (x)

\frac{sec ^{2} ( x ) - 1}{sec ( x ) - 1} = sec (x) + 1

sin (θ) - cos^{2} (θ) = sin^{3} (θ)

1 - tan^{2} (a) = cos (2 a) sec^{2} (a)

Is sin(z+w)=sin(z)cos(w)+cos(z)sin(w) ?
The answer to whether sin(z+w)=sin(z)cos(w)+cos(z)sin(w) is True