Is sin^2(θ)-2=-1-cos^2(θ) ?

The answer to whether sin^2(θ)-2=-1-cos^2(θ) is True

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prove sin^2(θ)-2=-1-cos^2(θ)

prove

sin^{2} (θ) - 2 = - 1 - cos^{2} (θ)

True

Solution steps

sin^{2} (θ) - 2 = - 1 - cos^{2} (θ)

Manipulating left side

sin^{2} (θ) - 2

Rewrite using trig identities

sin^{2} (θ) - 2

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

sin^{2} (x) = 1 - cos^{2} (x)

= 1 - cos^{2} (θ) - 2

Simplify

1 - cos^{2} (θ) - 2 : - cos^{2} (θ) - 1

1 - cos^{2} (θ) - 2

Group like terms

= - cos^{2} (θ) + 1 - 2

Add/Subtract the numbers:

1 - 2 = - 1

= - cos^{2} (θ) - 1

= - cos^{2} (θ) - 1

= - cos^{2} (θ) - 1

= - 1 - cos^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

sin (2 α) = 2 sin (α) cos (α)

cos (θ + π) = - cos (θ)

\frac{sec ^{2} ( θ ) - 1}{sin ( θ )} = tan (θ) sec (θ)

(1 + csc (x)) (1 + csc (- x)) = - cot^{2} (x)

cos (0) - sec (0) = - sin (0) tan (0)

Is sin^2(θ)-2=-1-cos^2(θ) ?
The answer to whether sin^2(θ)-2=-1-cos^2(θ) is True