Is cos(4a)=1-8sin^2(a)cos^2(a) ?

The answer to whether cos(4a)=1-8sin^2(a)cos^2(a) is True

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prove cos(4a)=1-8sin^2(a)cos^2(a)

prove

cos (4 a) = 1 - 8 sin^{2} (a) cos^{2} (a)

True

Solution steps

cos (4 a) = 1 - 8 sin^{2} (a) cos^{2} (a)

Manipulating left side

cos (4 a)

Rewrite using trig identities

cos (4 a)

= cos (2 \cdot 2 a)

Use the Double Angle identity:

cos (2 x) = 1 - 2 sin^{2} (x)

= 1 - 2 sin^{2} (2 a)

Use the Double Angle identity:

sin (2 x) = 2 sin (x) cos (x)

= 1 - 2 (2 sin (a) cos (a))^{2}

Simplify

1 - 2 (2 sin (a) cos (a))^{2} : 1 - 8 sin^{2} (a) cos^{2} (a)

1 - 2 (2 sin (a) cos (a))^{2}

2 (2 sin (a) cos (a))^{2} = 2^{3} sin^{2} (a) cos^{2} (a)

2 (2 sin (a) cos (a))^{2}

(2 sin (a) cos (a))^{2} = 2^{2} sin^{2} (a) cos^{2} (a)

(2 sin (a) cos (a))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 2^{2} sin^{2} (a) cos^{2} (a)

= 2^{2} \cdot 2 sin^{2} (a) cos^{2} (a)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2^{2} = 2^{1 + 2}

= 2^{1 + 2} sin^{2} (a) cos^{2} (a)

Add the numbers:

1 + 2 = 3

= 2^{3} sin^{2} (a) cos^{2} (a)

= 1 - 2^{3} sin^{2} (a) cos^{2} (a)

2^{3} = 8

= 1 - 8 sin^{2} (a) cos^{2} (a)

= 1 - 8 sin^{2} (a) cos^{2} (a)

= 1 - 8 sin^{2} (a) cos^{2} (a)

We showed that the two sides could take the same form

\Rightarrow True

(cos (x)) (tan (x) + cot (x)) = csc (x)

cos (2 0^{\circ}) = cos (θ) + cos (θ)

cos^{2} (x) - sin^{2} (x) = tan^{2} (x)

1 - cos (4 x) = 2 sin^{2} (2 x)

(1 - cos (x)) (1 + sec (x)) = sin (x) tan (x)

Is cos(4a)=1-8sin^2(a)cos^2(a) ?
The answer to whether cos(4a)=1-8sin^2(a)cos^2(a) is True