Is tan^2(x)+cot^2(x)=sec^2(x)csc^2(x) ?

The answer to whether tan^2(x)+cot^2(x)=sec^2(x)csc^2(x) is False

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prove tan^2(x)+cot^2(x)=sec^2(x)csc^2(x)

prove

tan^{2} (x) + cot^{2} (x) = sec^{2} (x) csc^{2} (x)

False

Solution steps

tan^{2} (x) + cot^{2} (x) = sec^{2} (x) csc^{2} (x)

Show that the two sides are not equal

For

tan^{2} (x) + cot^{2} (x) = sec^{2} (x) csc^{2} (x)

plug in

x = 1

tan^{2} (1) + cot^{2} (1) = 2.83780 \dots

tan^{2} (1) + cot^{2} (1)

Refine to a decimal form

= 2.83780 \dots

sec^{2} (1) csc^{2} (1) = 4.83780 \dots

sec^{2} (1) csc^{2} (1)

Refine to a decimal form

= 4.83780 \dots

The two sides are not equal

\Rightarrow False

tan^{4} (x) = \frac{( sin ^{4} ( x ) )}{cos ^{4} ( x )}

sin^{2} (π) = 1 - cos^{2} (π)

tan (π + x) = tan (x)

\frac{( cot ( x ) + tan ( x ) )}{cot ( x ) - tan ( x )} = sec (2 x)

cot (a) + tan (a) = sec (a) csc (a)

Is tan^2(x)+cot^2(x)=sec^2(x)csc^2(x) ?
The answer to whether tan^2(x)+cot^2(x)=sec^2(x)csc^2(x) is False