Is tan^2(x)=cos^2(tan^2(-1)) ?

The answer to whether tan^2(x)=cos^2(tan^2(-1)) is False

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prove tan^2(x)=cos^2(tan^2(-1))

prove

tan^{2} (x) = cos^{2} (tan^{2} (- 1))

False

Solution steps

tan^{2} (x) = cos^{2} (tan^{2} (- 1))

Show that the two sides are not equal

For

tan^{2} (x) = cos^{2} (tan^{2} (- 1))

plug in

x = 0

tan^{2} (0) = 0

tan^{2} (0)

Use the following trivial identity:

tan (0) = 0

tan (0)

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 0

= 0^{2}

Simplify

= 0

cos^{2} (tan^{2} (- 1)) = 0.56910 \dots

cos^{2} (tan^{2} (- 1))

Refine to a decimal form

= 0.56910 \dots

The two sides are not equal

\Rightarrow False

\frac{csc ( x ) - sin ( x )}{cot ( x )} = cos (x)

csc (x) sec (x) = 2 csc^{2} (x)

cos^{2} (x) cot^{2} (x) = cot^{2} (x) - cos^{2} (x)

sin^{2} (x) sec^{2} (x) = tan^{2} (x)

tan (4 5^{\circ} + x) + tan (4 5^{\circ} - x) = 2 sec (2 x)

Is tan^2(x)=cos^2(tan^2(-1)) ?
The answer to whether tan^2(x)=cos^2(tan^2(-1)) is False