Is prove-sin^2(θ)=cos^2(θ)-1 ?

The answer to whether prove-sin^2(θ)=cos^2(θ)-1 is True

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prove-sin^2(θ)=cos^2(θ)-1

prove

- sin^{2} (θ) = cos^{2} (θ) - 1

True

Solution steps

- sin^{2} (θ) = cos^{2} (θ) - 1

Manipulating right side

cos^{2} (θ) - 1

Rewrite using trig identities

cos^{2} (θ) - 1

Use the Pythagorean identity:

1 = cos^{2} (x) + sin^{2} (x)

1 - cos^{2} (x) = sin^{2} (x)

= - sin^{2} (θ)

= - sin^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

sec (x) + cos (x) = tan (x) sin (x)

\frac{sin ( x ) + tan ( x )}{cos ( x ) + 1} = tan (x)

cos^{2} (2 x) = \frac{1}{2} + \frac{1}{2} cos (4 x)

cot (x) + \frac{cos ( x )}{1 - cos ( x )} = sin (x)

\frac{csc ( x ) - 1}{1 - sin ( x )} = csc (x)

Is prove-sin^2(θ)=cos^2(θ)-1 ?
The answer to whether prove-sin^2(θ)=cos^2(θ)-1 is True