Is 2cos(x)-2cos^3(x)=sin(x)sin^2(x) ?

The answer to whether 2cos(x)-2cos^3(x)=sin(x)sin^2(x) is False

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prove 2cos(x)-2cos^3(x)=sin(x)sin^2(x)

prove

2 cos (x) - 2 cos^{3} (x) = sin (x) sin^{2} (x)

False

Solution steps

2 cos (x) - 2 cos^{3} (x) = sin (x) sin^{2} (x)

Show that the two sides are not equal

For

2 cos (x) - 2 cos^{3} (x) = sin (x) sin^{2} (x)

plug in

x = 1

2 cos (1) - 2 cos^{3} (1) = 0.76514 \dots

2 cos (1) - 2 cos^{3} (1)

Refine to a decimal form

= 0.76514 \dots

sin (1) sin^{2} (1) = 0.59582 \dots

sin (1) sin^{2} (1)

Refine to a decimal form

= 0.59582 \dots

The two sides are not equal

\Rightarrow False

\frac{1}{1 + sin ( t )} = \frac{1 - sin ( t )}{cos ^{2} ( t )}

1 + tan^{2} (A) = sec^{3} (A) cos (A)

sec (0) - cos (0) = tan (0) sin (0)

sin (x) - csc (x) = - cot (x) cos (x)

1 - sin (θ) cos (θ) tan (θ) = cos^{2} (θ)

Is 2cos(x)-2cos^3(x)=sin(x)sin^2(x) ?
The answer to whether 2cos(x)-2cos^3(x)=sin(x)sin^2(x) is False