Is (cos(2θ))/(sin^2(θ))=2cos^2(θ) ?

The answer to whether (cos(2θ))/(sin^2(θ))=2cos^2(θ) is False

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prove (cos(2θ))/(sin^2(θ))=2cos^2(θ)

prove

\frac{cos ( 2 θ )}{sin ^{2} ( θ )} = 2 cos^{2} (θ)

False

Solution steps

\frac{cos ( 2 θ )}{sin ^{2} ( θ )} = 2 cos^{2} (θ)

Show that the two sides are not equal

For

\frac{cos ( 2 θ )}{sin ^{2} ( θ )} = 2 cos^{2} (θ)

plug in

θ = 1

\frac{cos ( 2 \cdot 1 )}{sin ^{2} ( 1 )} = - 0.58771 \dots

\frac{cos ( 2 \cdot 1 )}{sin ^{2} ( 1 )}

Refine to a decimal form

= - 0.58771 \dots

2 cos^{2} (1) = 0.58385 \dots

2 cos^{2} (1)

Refine to a decimal form

= 0.58385 \dots

The two sides are not equal

\Rightarrow False

sec^{2} (θ) - tan (θ) cot (θ) = tan^{2} (θ)

csc^{2} (θ) (1 - cos^{2} (θ)) = tan (42 0^{\circ})

\frac{sin ^{2} ( θ )}{1 - sin ^{2} ( θ )} = tan^{2} (θ)

tan^{4} (x) = (1 - sec^{2} (x))^{2}

- 2 sin (x) = - sin (2 x)

Is (cos(2θ))/(sin^2(θ))=2cos^2(θ) ?
The answer to whether (cos(2θ))/(sin^2(θ))=2cos^2(θ) is False