Is 1=sec^2(θ)-tan^2(θ) ?

The answer to whether 1=sec^2(θ)-tan^2(θ) is True

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prove 1=sec^2(θ)-tan^2(θ)

prove

1 = sec^{2} (θ) - tan^{2} (θ)

True

Solution steps

1 = sec^{2} (θ) - tan^{2} (θ)

Use the Pythagorean identity:

tan^{2} (x) + 1 = sec^{2} (x)

1 = sec^{2} (x) - tan^{2} (x)

\Rightarrow True

\frac{1}{sin ( θ ) cot ( θ )} = \frac{1}{cos ( θ )}

tan^{8} (x) = tan^{6} (x) sec^{2} (x) - tan^{6} (x)

2 (sin (2 y) cos (2 y)) = sin (4 y)

csc^{2} (θ) \cdot (sin^{2} (θ)) = 1

tan (b) cos (b) + cot (b) cos (b) = csc (b)