Is csc(x)-1=(2sin(x))/(sin(x)) ?

The answer to whether csc(x)-1=(2sin(x))/(sin(x)) is False

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prove csc(x)-1=(2sin(x))/(sin(x))

prove

csc (x) - 1 = \frac{2 sin ( x )}{sin ( x )}

False

Solution steps

csc (x) - 1 = \frac{2 sin ( x )}{sin ( x )}

Show that the two sides are not equal

For

csc (x) - 1 = \frac{2 sin ( x )}{sin ( x )}

plug in

x = 1

csc (1) - 1 = 0.18839 \dots

csc (1) - 1

Refine to a decimal form

= 0.18839 \dots

\frac{2 sin ( 1 )}{sin ( 1 )} = 2

\frac{2 sin ( 1 )}{sin ( 1 )}

\frac{2 sin ( 1 )}{sin ( 1 )} = 2

\frac{2 sin ( 1 )}{sin ( 1 )}

Cancel the common factor:

sin (1)

= 2

= 2

The two sides are not equal

\Rightarrow False

2 sin^{2} (θ) - cos (2 θ) = 1

\frac{1}{csc ( + 1 )} + \frac{1}{sin ( x ) + 1} = 1

\frac{( tan ^{2} ( t ) )}{sec ( t )} = sec (t) - cos (t)

\frac{tan ( a ) sin ( a )}{sec ( a ) - 1} = 1 + cos (a)

3 sin (2 x) = 6 sin (x) cos (x)

Is csc(x)-1=(2sin(x))/(sin(x)) ?
The answer to whether csc(x)-1=(2sin(x))/(sin(x)) is False