What is the general solution for 2tan^2(x)-2=0 ?

The general solution for 2tan^2(x)-2=0 is x= pi/4+pin,x=(3pi)/4+pin

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2tan^2(x)-2=0

2 tan^{2} (x) - 2 = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

2 tan^{2} (x) - 2 = 0

Solve by substitution

tan (x) = 1, tan (x) = - 1

tan (x) = 1 : x = \frac{π}{4} + πn

tan (x) = - 1 : x = \frac{3 π}{4} + πn

Combine all the solutions

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

cos (2 x) = - \frac{1}{2}

cos (x) = 5

2 cos (θ) - 3 = 0

tan (π)

cos^{2} (6 0^{\circ})

What is the general solution for 2tan^2(x)-2=0 ?
The general solution for 2tan^2(x)-2=0 is x= pi/4+pin,x=(3pi)/4+pin