Is (cos(b))/(sin(b))sin(b)=cos(b) ?

The answer to whether (cos(b))/(sin(b))sin(b)=cos(b) is True

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prove (cos(b))/(sin(b))sin(b)=cos(b)

prove

\frac{cos ( b )}{sin ( b )} sin (b) = cos (b)

True

Solution steps

\frac{cos ( b )}{sin ( b )} sin (b) = cos (b)

Manipulating left side

\frac{cos ( b )}{sin ( b )} sin (b)

Simplify

\frac{cos ( b )}{sin ( b )} sin (b) : cos (b)

\frac{cos ( b )}{sin ( b )} sin (b)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{cos ( b ) sin ( b )}{sin ( b )}

Cancel the common factor:

sin (b)

= cos (b)

= cos (b)

We showed that the two sides could take the same form

\Rightarrow True

tan^{2} (θ) = \frac{sin ^{2} ( θ )}{cos ^{2} ( θ )}

1 + \frac{tan ^{2} ( A )}{1 + sec ( A )} = sec (A)

sin (x - \frac{π}{6}) + cos (x) = sin (x + π)

tan^{2} (2 3^{\circ}) - sec^{2} (2 3^{\circ}) = - 1

(1 - cos^{2} (t)) (1 + cos^{2} (t)) = 1

Is (cos(b))/(sin(b))sin(b)=cos(b) ?
The answer to whether (cos(b))/(sin(b))sin(b)=cos(b) is True