Is csc(x)-sin(x)=cot(x)-cos(x) ?

The answer to whether csc(x)-sin(x)=cot(x)-cos(x) is False

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prove csc(x)-sin(x)=cot(x)-cos(x)

prove

csc (x) - sin (x) = cot (x) - cos (x)

False

Solution steps

csc (x) - sin (x) = cot (x) - cos (x)

Show that the two sides are not equal

For

csc (x) - sin (x) = cot (x) - cos (x)

plug in

x = 1

csc (1) - sin (1) = 0.34692 \dots

csc (1) - sin (1)

Refine to a decimal form

= 0.34692 \dots

cot (1) - cos (1) = 0.10179 \dots

cot (1) - cos (1)

Refine to a decimal form

= 0.10179 \dots

The two sides are not equal

\Rightarrow False

sin^{4} (β) - cos^{4} (β) = 2 sin^{2} (β) - 1

3 + cos (2 y) = 2 + 2 cos^{2} (y)

\frac{1 - sin ^{4} ( x )}{cos ^{4} ( x )} = 1 + 2 tan (x)

cos (x) arcsin (x) = \frac{cos ( x )}{sin ( x )}

\frac{sin ( π - x )}{sin ( \frac{π}{2} - x )} = tan (x)

Is csc(x)-sin(x)=cot(x)-cos(x) ?
The answer to whether csc(x)-sin(x)=cot(x)-cos(x) is False