Is sin(x)sec(x)+cos(x)sec(x)=sec^2(x) ?

The answer to whether sin(x)sec(x)+cos(x)sec(x)=sec^2(x) is False

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prove sin(x)sec(x)+cos(x)sec(x)=sec^2(x)

prove

sin (x) sec (x) + cos (x) sec (x) = sec^{2} (x)

False

Solution steps

sin (x) sec (x) + cos (x) sec (x) = sec^{2} (x)

Show that the two sides are not equal

For

sin (x) sec (x) + cos (x) sec (x) = sec^{2} (x)

plug in

x = 1

sin (1) sec (1) + cos (1) sec (1) = 2.55740 \dots

sin (1) sec (1) + cos (1) sec (1)

Refine to a decimal form

= 2.55740 \dots

sec^{2} (1) = 3.42551 \dots

sec^{2} (1)

Refine to a decimal form

= 3.42551 \dots

The two sides are not equal

\Rightarrow False

81 - 9 (3 sin (x))^{2} = sec^{4} (x)

sin (4 0^{\circ}) = 2 sin (2 0^{\circ}) cos (2 0^{\circ})

sin (θ) - cos^{2} (θ) sin (θ) = sin^{3} (θ)

\frac{9}{sec ( x ) + 1} - \frac{9}{sec ( x ) - 1} = 0

sec^{2} (x) + csc^{2} (x) = (sec (x) csc (x))^{2}

Is sin(x)sec(x)+cos(x)sec(x)=sec^2(x) ?
The answer to whether sin(x)sec(x)+cos(x)sec(x)=sec^2(x) is False