Is csc(-x)-sin(-x)=cos(x)cot(x) ?

The answer to whether csc(-x)-sin(-x)=cos(x)cot(x) is False

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prove csc(-x)-sin(-x)=cos(x)cot(x)

prove

csc (- x) - sin (- x) = cos (x) cot (x)

False

Solution steps

csc (- x) - sin (- x) = cos (x) cot (x)

Show that the two sides are not equal

For

csc (- x) - sin (- x) = cos (x) cot (x)

plug in

x = 1

csc (- 1) - sin (- 1) = - 0.34692 \dots

csc (- 1) - sin (- 1)

Refine to a decimal form

= - 0.34692 \dots

cos (1) cot (1) = 0.34692 \dots

cos (1) cot (1)

Refine to a decimal form

= 0.34692 \dots

The two sides are not equal

\Rightarrow False

cos (20 π - x) + sin (\frac{83 π}{2} + x) = 0

\frac{1}{cot ( a ) + tan ( a )} = sin (a) cos (a)

sin (x) sin (2 x) + cos (x) cos (2 x) = cos (x)

45 - 25 sin (- 120 π t) = 45 + 25 sin (120 π t)

\frac{cot ^{2} ( x ) - 1}{cot ^{2} ( x ) + 1} = cos (2 x)

Is csc(-x)-sin(-x)=cos(x)cot(x) ?
The answer to whether csc(-x)-sin(-x)=cos(x)cot(x) is False