Is sin(x)+(cos^2(x))/(sin(x))=csc(x) ?

The answer to whether sin(x)+(cos^2(x))/(sin(x))=csc(x) is True

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prove sin(x)+(cos^2(x))/(sin(x))=csc(x)

prove

sin (x) + \frac{cos ^{2} ( x )}{sin ( x )} = csc (x)

True

Solution steps

sin (x) + \frac{cos ^{2} ( x )}{sin ( x )} = csc (x)

Manipulating right side

csc (x)

Express with sin, cos

csc (x)

Use the basic trigonometric identity:

csc (x) = \frac{1}{sin ( x )}

= \frac{1}{sin ( x )}

= \frac{1}{sin ( x )}

Rewrite using trig identities

\frac{1}{sin ( x )}

Use the Pythagorean identity:

1 = cos^{2} (x) + sin^{2} (x)

= \frac{cos ^{2} ( x ) + sin ^{2} ( x )}{sin ( x )}

= \frac{cos ^{2} ( x ) + sin ^{2} ( x )}{sin ( x )}

Expand

\frac{cos ^{2} ( x ) + sin ^{2} ( x )}{sin ( x )} : \frac{cos ^{2} ( x )}{sin ( x )} + sin (x)

\frac{cos ^{2} ( x ) + sin ^{2} ( x )}{sin ( x )}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{cos ^{2} ( x ) + sin ^{2} ( x )}{sin ( x )} = \frac{cos ^{2} ( x )}{sin ( x )} + \frac{sin ^{2} ( x )}{sin ( x )}

= \frac{cos ^{2} ( x )}{sin ( x )} + \frac{sin ^{2} ( x )}{sin ( x )}

Cancel

\frac{sin ^{2} ( x )}{sin ( x )} : sin (x)

\frac{sin ^{2} ( x )}{sin ( x )}

Cancel the common factor:

sin (x)

= sin (x)

= \frac{cos ^{2} ( x )}{sin ( x )} + sin (x)

= \frac{cos ^{2} ( x )}{sin ( x )} + sin (x)

= sin (x) + \frac{cos ^{2} ( x )}{sin ( x )}

We showed that the two sides could take the same form

\Rightarrow True

\frac{cos ( x ) + 1}{sin ( x ) + tan ( x )} = cot (x)

sin (3 x) + sin (x) = 2 sin (2 x) cos (x)

cos (A + B) = cos (A) cos (B) - sin (A) sin (B)

tan^{2} (A) + 1 = \frac{sec ( A )}{cos ( A )}

\frac{2 cot ( x )}{1 + cot ^{2} ( x )} = sin (2 x)

Is sin(x)+(cos^2(x))/(sin(x))=csc(x) ?
The answer to whether sin(x)+(cos^2(x))/(sin(x))=csc(x) is True