Is (-1+sec^2(a))/(-tan(a))=-tan(a) ?

The answer to whether (-1+sec^2(a))/(-tan(a))=-tan(a) is True

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prove (-1+sec^2(a))/(-tan(a))=-tan(a)

prove

\frac{- 1 + sec ^{2} ( a )}{- tan ( a )} = - tan (a)

True

Solution steps

\frac{- 1 + sec ^{2} ( a )}{- tan ( a )} = - tan (a)

Manipulating left side

\frac{- 1 + sec ^{2} ( a )}{- tan ( a )}

Rewrite using trig identities

= - tan (a)

We showed that the two sides could take the same form

\Rightarrow True

tan^{2} (x) (1 + cos (2 x)) = sin^{2} (x)

\frac{tan ( x )}{csc ( x )} = \frac{1}{cos ( x )} - \frac{1}{sec ( x )}

\frac{sin ^{2} ( 2 x )}{1 - cos ( 2 x )} = 2 cos^{2} (x)

tan (θ) sec^{2} (θ) tan (θ) = tan^{3} (θ)

1 - 2 sin^{2} (\frac{x}{4}) = cos (\frac{x}{2})

Is (-1+sec^2(a))/(-tan(a))=-tan(a) ?
The answer to whether (-1+sec^2(a))/(-tan(a))=-tan(a) is True