Is 2sin((3pi)/2)=-2+cos((3pi)/2) ?

The answer to whether 2sin((3pi)/2)=-2+cos((3pi)/2) is True

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prove 2sin((3pi)/2)=-2+cos((3pi)/2)

prove

2 sin (\frac{3 π}{2}) = - 2 + cos (\frac{3 π}{2})

True

Solution steps

2 sin (\frac{3 π}{2}) = - 2 + cos (\frac{3 π}{2})

Manipulating left side

2 sin (\frac{3 π}{2})

Simplify

2 sin (\frac{3 π}{2}) : - 2

= - 2

Manipulating right side

- 2 + cos (\frac{3 π}{2})

Simplify

- 2 + cos (\frac{3 π}{2}) : - 2

= - 2

We showed that the two sides could take the same form

\Rightarrow True

(sec (x) - tan (x))^{2} = tan (x) cot (x)

sin (x) = \frac{tan ( x ) cot ( x )}{csc ( x )}

cos (x) - sec (x) = cos (x) - \frac{1}{cos ( x )}

\frac{cot ^{3} ( t )}{csc ( t )} = cos (t) cot^{2} (t)

\frac{tan ( 2 x )}{1 + sec ( 2 x )} = tan (x)

Is 2sin((3pi)/2)=-2+cos((3pi)/2) ?
The answer to whether 2sin((3pi)/2)=-2+cos((3pi)/2) is True