Is cot(y/2)=(sin(y))/(1-cos(y)) ?

The answer to whether cot(y/2)=(sin(y))/(1-cos(y)) is True

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prove cot(y/2)=(sin(y))/(1-cos(y))

prove

cot (\frac{y}{2}) = \frac{sin ( y )}{1 - cos ( y )}

True

Solution steps

cot (\frac{y}{2}) = \frac{sin ( y )}{1 - cos ( y )}

Let:

u = \frac{y}{2}

cot (u) = \frac{sin ( 2 u )}{1 - cos ( 2 u )}

Prove

cot (u) = \frac{sin ( 2 u )}{1 - cos ( 2 u )} :

True

Therefore

cot (\frac{y}{2}) = \frac{sin ( y )}{1 - cos ( y )}

We showed that the two sides could take the same form

\Rightarrow True

cot (- θ) \cdot cos (- θ) + sin (- θ) = - csc (θ)

cot^{2} (x) - csc^{2} (x) = 1

(sin (θ) - cos (θ))^{2} - 1 = - 2 sin (θ) cos (θ)

tan^{2} (2 π) = tan (2 π)

sec (θ) cot (θ) - sin (θ) = cos (θ) cot (θ)

Is cot(y/2)=(sin(y))/(1-cos(y)) ?
The answer to whether cot(y/2)=(sin(y))/(1-cos(y)) is True