Is 4sec^2(θ)-3=1+4tan^2(θ) ?

The answer to whether 4sec^2(θ)-3=1+4tan^2(θ) is True

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prove 4sec^2(θ)-3=1+4tan^2(θ)

prove

4 sec^{2} (θ) - 3 = 1 + 4 tan^{2} (θ)

True

Solution steps

4 sec^{2} (θ) - 3 = 1 + 4 tan^{2} (θ)

Manipulating left side

4 sec^{2} (θ) - 3

Rewrite using trig identities

= 4 tan^{2} (θ) + 1

= 1 + 4 tan^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

sec (θ) = csc (θ) tan (θ)

- sin (x) = sin (x)

\frac{csc ^{2} ( x ) + 1}{cot ^{2} ( x )} = \frac{1 + sin ^{2} ( x )}{cos ^{2} ( x )}

sec (x) + tan (x) = (\frac{1}{sec ( x ) - tan ( x )})

(sec (a) - tan (a)) (sec (a) + tan (a)) = 1

Is 4sec^2(θ)-3=1+4tan^2(θ) ?
The answer to whether 4sec^2(θ)-3=1+4tan^2(θ) is True