Is 1/(cos(θ)sin(θ))=sec(θ)csc(θ) ?

The answer to whether 1/(cos(θ)sin(θ))=sec(θ)csc(θ) is True

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prove 1/(cos(θ)sin(θ))=sec(θ)csc(θ)

prove

\frac{1}{cos ( θ ) sin ( θ )} = sec (θ) csc (θ)

True

Solution steps

\frac{1}{cos ( θ ) sin ( θ )} = sec (θ) csc (θ)

Manipulating right side

sec (θ) csc (θ)

Express with sin, cos

= \frac{1}{cos ( θ ) sin ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

csc (\frac{π}{2 - x}) cot (x) = csc (x)

\frac{csc ( x ) + sec ( x )}{1 + tan ( x )} = csc (x)

(3) \frac{( cos ^{2} ( 2 z ) )}{2} = \frac{3 cos ( 4 z )}{4}

cos^{2} (x) (cot^{2} (x) + 1) = cot^{2} (x)

sin (\frac{π}{6} + x) = cos (\frac{π}{3} - x)

Is 1/(cos(θ)sin(θ))=sec(θ)csc(θ) ?
The answer to whether 1/(cos(θ)sin(θ))=sec(θ)csc(θ) is True