Is 1-cos^2(x)tan^2(x)=cos^2(x) ?

The answer to whether 1-cos^2(x)tan^2(x)=cos^2(x) is True

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prove 1-cos^2(x)tan^2(x)=cos^2(x)

prove

1 - cos^{2} (x) tan^{2} (x) = cos^{2} (x)

True

Solution steps

1 - cos^{2} (x) tan^{2} (x) = cos^{2} (x)

Manipulating left side

1 - cos^{2} (x) tan^{2} (x)

Express with sin, cos

= 1 - sin^{2} (x)

Rewrite using trig identities

= cos^{2} (x)

We showed that the two sides could take the same form

\Rightarrow True

cot (2 a) = \frac{1}{2} (cot (a) - tan (a))

sec (t) = \frac{cot ( t ) + tan ( t )}{csc ( t )}

\frac{1 - cos ( 2 a )}{sin ( 2 a )} = tan (a)

sin (2 x) + sin (x) = sin (3 x)

tan^{2} (x) = \frac{1}{cot ^{2} ( x )}

Is 1-cos^2(x)tan^2(x)=cos^2(x) ?
The answer to whether 1-cos^2(x)tan^2(x)=cos^2(x) is True