Is sec^2(x)cos(x)-sec(x)=0 ?

The answer to whether sec^2(x)cos(x)-sec(x)=0 is True

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prove sec^2(x)cos(x)-sec(x)=0

prove

sec^{2} (x) cos (x) - sec (x) = 0

True

Solution steps

sec^{2} (x) cos (x) - sec (x) = 0

Manipulating left side

sec^{2} (x) cos (x) - sec (x)

Express with sin, cos

= 0

We showed that the two sides could take the same form

\Rightarrow True

sin^{4} (x) = (1 - cos^{2} (x))^{2}

sec (z) cot (z) sin (z) = 1

cos (θ) = \frac{2}{3}

cos (4 x) + sin (4 x) = cos (2 x)

\frac{sec ( x ) - 1}{sec ( x )} = 2 sin^{2} (\frac{x}{2})

Is sec^2(x)cos(x)-sec(x)=0 ?
The answer to whether sec^2(x)cos(x)-sec(x)=0 is True