Is (sin^2(θ))/(tan^2(θ))=cos^2(θ) ?

The answer to whether (sin^2(θ))/(tan^2(θ))=cos^2(θ) is True

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prove (sin^2(θ))/(tan^2(θ))=cos^2(θ)

prove

\frac{sin ^{2} ( θ )}{tan ^{2} ( θ )} = cos^{2} (θ)

True

Solution steps

\frac{sin ^{2} ( θ )}{tan ^{2} ( θ )} = cos^{2} (θ)

Manipulating left side

\frac{sin ^{2} ( θ )}{tan ^{2} ( θ )}

Express with sin, cos

= cos^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

sin (x) + sin (y) = 2 sin (\frac{x + y}{2}) cos (\frac{x - y}{2})

sec^{2} (θ) - 2 tan (θ) = (tan (θ) - 1)^{2}

\frac{1}{csc ( x )} + 1 = sin (x) + 1

25 sin^{2} (x) + 25 cos^{2} (x) = 25

cot (x) sin (x) sec (x) = 1

Is (sin^2(θ))/(tan^2(θ))=cos^2(θ) ?
The answer to whether (sin^2(θ))/(tan^2(θ))=cos^2(θ) is True