Is (cos(t)+1)/(sin(t)+sec(t))=(tan(t))/(sec(t)-1) ?

The answer to whether (cos(t)+1)/(sin(t)+sec(t))=(tan(t))/(sec(t)-1) is False

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prove (cos(t)+1)/(sin(t)+sec(t))=(tan(t))/(sec(t)-1)

prove

\frac{cos ( t ) + 1}{sin ( t ) + sec ( t )} = \frac{tan ( t )}{sec ( t ) - 1}

False

Solution steps

\frac{cos ( t ) + 1}{sin ( t ) + sec ( t )} = \frac{tan ( t )}{sec ( t ) - 1}

Show that the two sides are not equal

\Rightarrow False

\frac{cot ( θ ) - tan ( θ )}{cot ( θ ) + tan ( θ )} = cos (2 θ)

cos^{2} (2 x) + 4 sin^{2} (x) cos^{2} (x) = 1

cos (x) (sec (x) - 1) = 1 - cos (x)

3 sec^{2} (33 0^{\circ}) tan (33 0^{\circ}) = 4 tan (33 0^{\circ})

(sin (x)) (cot (x)) = (cos (x))

Is (cos(t)+1)/(sin(t)+sec(t))=(tan(t))/(sec(t)-1) ?
The answer to whether (cos(t)+1)/(sin(t)+sec(t))=(tan(t))/(sec(t)-1) is False